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# From: http://www.ruby-forum.com/topic/111524 # Author: Daniel Martin a = Hash.new{|h,k| h[k]=Hash.new(&h.default_proc) } a[2][1]=2 a[2][2][3]=4 a[3][1][1][1]=1 p a #=> {2=>{1=>2, 2=>{3=>4}}, 3=>{1=>{1=>{1=>1}}}}
URL: http://www.ruby-forum.com/topic/111524
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