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Ruby class for easy version number natural order sorting

/ Published in: Ruby
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Probably not the most elegant solution, but it works. Needed this for a capistrano deploy task which shows the most recent tagged releases in my repository. Very bare bones, and needs tweaking if your versions are not in X.X.X.X format.

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  1. class Version
  2.   include Comparable
  3.  
  4.   attr_reader :major, :feature_group, :feature, :bugfix
  5.  
  6.   def initialize(version="")
  7.     v = version.split(".")
  8.     @major = v[0].to_i
  9.     @feature_group = v[1].to_i
  10.     @feature = v[2].to_i
  11.     @bugfix = v[3].to_i
  12.   end
  13.  
  14.   def <=>(other)
  15.     return @major <=> other.major if ((@major <=> other.major) != 0)
  16.     return @feature_group <=> other.feature_group if ((@feature_group <=> other.feature_group) != 0)
  17.     return @feature <=> other.feature if ((@feature <=> other.feature) != 0)
  18.     return @bugfix <=> other.bugfix
  19.   end
  20.  
  21.   def self.sort
  22.     self.sort!{|a,b| a <=> b}
  23.   end
  24.  
  25.   def to_s
  26.     @major.to_s + "." + @feature_group.to_s + "." + @feature.to_s + "." + @bugfix.to_s
  27.   end
  28. end
  29.  
  30. ## Example Usage:
  31. ##  list = []
  32. ##  ["1.2.2.10","1.2.2.1","2.1.10.2","2.3.4.1"].each {|v| list.push(Version.new(v)) }
  33. ##  list.sort.each{|v| pp v.to_s }
  34. ##
  35. ###"1.2.2.1"
  36. ###"1.2.2.10"
  37. ###"2.1.10.2"
  38. ###"2.3.4.1"

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