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Revision: 68423
at January 18, 2015 06:46 by igotepava


Initial Code
struct element{
	int label, used;
};

struct tree{
	element elements[10000];
};

tree *InitB(int x, tree *T){
	T = new tree;
	for(int i=0; i<10000; i++){
		T->elements[i].used = 0;
		T->elements[i].label = -1;
	}
	T->elements[1].label = x;
	T->elements[1].used = 1;
	return T;
}

int RootB(tree *T){
	return T->elements[1].label;
}

int ParentB(int n, tree *T){
	if(T->elements[1].label == n) return -1;
	if(n%2) return n/2+1;
	else return n/2;
}

int LeftChildB(int n, tree *T){
	if(!(T->elements[n*2].used)) return -1;
	else return T->elements[n*2].label;
}

int RightChildB(int n, tree *T){
	if(!(T->elements[n*2+1].used)) return -1;
	else return n*2+1;
}

int LabelB(int n, tree *T){
	return T->elements[n].label;
}

void ChangeLabelB(int x, int n, tree *T){
	T->elements[n].label = x;
}

void CreateLeftB(int x, int n, tree *T){
	if(T->elements[n*2].used) cout << "Mjesto je zauzeto!\n";
	else{
		T->elements[n*2].used = 1;
		T->elements[n*2].label = x;
	}
}

void CreateRightB(int x, int n, tree *T){
	if(T->elements[n*2+1].used) cout << "Mjesto je zauzeto!\n";
	else{
		T->elements[n*2+1].used = 1;
		T->elements[n*2+1].label = x;
	}
}

void DeleteB(int n, tree *T){
	if(LeftChildB(n, T) != -1) DeleteB(LeftChildB(n, T), T);
	if(RightChildB(n, T) != -1) DeleteB(RightChildB(n, T), T);
	T->elements[n].label = -1;
	T->elements[n].used = 0;
}

Initial URL

                                

Initial Description
Implementacija binarnog stabla pomoću polja.

Initial Title
binarno_stablo_polje.h

Initial Tags
data, array

Initial Language
C++